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x^2-25x=-156
We move all terms to the left:
x^2-25x-(-156)=0
We add all the numbers together, and all the variables
x^2-25x+156=0
a = 1; b = -25; c = +156;
Δ = b2-4ac
Δ = -252-4·1·156
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-1}{2*1}=\frac{24}{2} =12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+1}{2*1}=\frac{26}{2} =13 $
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